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Hi everyone, I have an application that was migrated from on provider to another. From the new provider when a user logon it took around 5 minutes. Provider tell us that all is OK from their part. From my workstation I have run wireshark and find this in the frame :

1846    07:40:20,504    141.288 141.288268000   192.168.8.7 10.241.70.31    TCP 18  1522    129 262800  54525   1522 → 54525 [PSH, ACK] Seq=7915 Ack=6362 Win=262800 Len=75

2953    07:42:41,955    141.330 141.330132000   192.168.8.7 10.241.70.31    TCP 18  1522    127 262800  54525   1522 → 54525 [PSH, ACK] Seq=8062 Ack=6697 Win=262800 Len=73

N.B. I'm new and can't upload a screenshot or the pcapng file :-(.

Wireshark Printscreen

Wireshark full Full wireshark trace

Anyway I find the delay spend between my workstation and the application server (141 * 2 = 4.7 s).

I also noticed that the TTL (frame 1846 & 2953) is 60. Is it correct if I said there is 68 (128-60) network componant between my workstation (192.168.8.7) and the Oracle server (10.21.70.31) ? How can I know where the time is spend ?

Hi everyone, I have an application that was migrated from on provider to another. From the new provider when a user logon it took around 5 minutes. Provider tell us that all is OK from their part. From my workstation I have run wireshark and find this in the frame :

1846    07:40:20,504    141.288 141.288268000   192.168.8.7 10.241.70.31    TCP 18  1522    129 262800  54525   1522 → 54525 [PSH, ACK] Seq=7915 Ack=6362 Win=262800 Len=75

2953    07:42:41,955    141.330 141.330132000   192.168.8.7 10.241.70.31    TCP 18  1522    127 262800  54525   1522 → 54525 [PSH, ACK] Seq=8062 Ack=6697 Win=262800 Len=73

N.B. I'm new and can't upload a screenshot or the pcapng file :-(.

Printscreen

Full wireshark trace

Anyway I find the delay spend between my workstation and the application server (141 * 2 = 4.7 s).

I also noticed that the TTL (frame 1846 & 2953) is 60. Is it correct if I said there is 68 (128-60) network componant between my workstation (192.168.8.7) and the Oracle server (10.21.70.31) ? How can I know where the time is spend ?

Hi everyone, I have an application that was migrated from on provider to another. From the new provider when a user logon it took around 5 minutes. Provider tell us that all is OK from their part. From my workstation I have run wireshark and find this in the frame :

1846    07:40:20,504    141.288 141.288268000   192.168.8.7 10.241.70.31    TCP 18  1522    129 262800  54525   1522 → 54525 [PSH, ACK] Seq=7915 Ack=6362 Win=262800 Len=75

2953    07:42:41,955    141.330 141.330132000   192.168.8.7 10.241.70.31    TCP 18  1522    127 262800  54525   1522 → 54525 [PSH, ACK] Seq=8062 Ack=6697 Win=262800 Len=73

N.B. I'm new and can't upload a screenshot or the pcapng file :-(.

Printscreen

Full wireshark trace

Anyway I find the delay spend between my workstation and the application server (141 * 2 = 4.7 s).

I also noticed that the TTL (frame 1846 & 2953) is 60. Is it correct if I said there is 68 (128-60) network componant between my workstation (192.168.8.7) and the Oracle server (10.21.70.31) ? How can I know where the time is spend ?

Hi everyone, I have an application that was migrated from on provider to another. From the new provider when a user logon it took around 5 minutes. Provider tell us that all is OK from their part. From my workstation I have run wireshark and find this in the frame :

1846    07:40:20,504    141.288 141.288268000   192.168.8.7 10.241.70.31    TCP 18  1522    129 262800  54525   1522 → 54525 [PSH, ACK] Seq=7915 Ack=6362 Win=262800 Len=75

2953    07:42:41,955    141.330 141.330132000   192.168.8.7 10.241.70.31    TCP 18  1522    127 262800  54525   1522 → 54525 [PSH, ACK] Seq=8062 Ack=6697 Win=262800 Len=73

N.B. I'm new and can't upload a screenshot or the pcapng file :-(.

Full wireshark tracelink text

Anyway I find the delay spend between my workstation and the application server (141 * 2 = 4.7 s).

I also noticed that the TTL (frame 1846 & 2953) is 60. Is it correct if I said there is 68 (128-60) network componant between my workstation (192.168.8.7) and the Oracle server (10.21.70.31) ? How can I know where the time is spend ?

Hi everyone, I have an application that was migrated from on provider to another. From the new provider when a user logon it took around 5 minutes. Provider tell us that all is OK from their part. From my workstation I have run wireshark and find this in the frame :

1846    07:40:20,504    141.288 141.288268000   192.168.8.7 10.241.70.31    TCP 18  1522    129 262800  54525   1522 → 54525 [PSH, ACK] Seq=7915 Ack=6362 Win=262800 Len=75

2953    07:42:41,955    141.330 141.330132000   192.168.8.7 10.241.70.31    TCP 18  1522    127 262800  54525   1522 → 54525 [PSH, ACK] Seq=8062 Ack=6697 Win=262800 Len=73

N.B. I'm new and can't upload a screenshot or the pcapng file :-(.

link text

Anyway I find the delay spend between my workstation and the application server (141 * 2 = 4.7 s).

I also noticed that the TTL (frame 1846 & 2953) is 60. Is it correct if I said there is 68 (128-60) network componant between my workstation (192.168.8.7) and the Oracle server (10.21.70.31) ? How can I know where the time is spend ?

Hi everyone, I have an application that was migrated from on provider to another. From the new provider when a user logon it took around 5 minutes. Provider tell us that all is OK from their part. From my workstation I have run wireshark wireshak and find this in the frame trame :

1846    07:40:20,504    141.288 141.288268000 141.288268000   192.168.8.7 10.241.70.31    TCP 18  1522    129 262800  54525   1522 → 54525 [PSH, ACK] Seq=7915 Ack=6362 Win=262800 Len=75

Len=75
 
2953    07:42:41,955    141.330 141.330132000 141.330132000   192.168.8.7 10.241.70.31    TCP 18  1522    127 262800  54525   1522 → 54525 [PSH, ACK] Seq=8062 Ack=6697 Win=262800 Len=73

N.B. I'm new and can't upload a screenshot or the pcapng file :-(.

Anyway I find the delay spend between my workstation and the application server (141 * 2 = 4.7 s).

I also noticed that the TTL (frame 1846 & 2953) is 60. Is it correct if I said there is 68 (128-60) network componant between my workstation (192.168.8.7) and the Oracle server (10.21.70.31) ? How can I know where the time is spend ?

Hi everyone, I have an application that was migrated from on provider to another. From the new provider when a user logon it took around 5 minutes. Provider tell us that all is OK from their part. From my workstation I have run wireshak and find this in the trame :

1846 07:40:20,504 141.288 141.288268000 192.168.8.7 10.241.70.31 TCP 18 1522 129 262800 54525 1522 → 54525 [PSH, ACK] Seq=7915 Ack=6362 Win=262800 Len=75

2953 07:42:41,955 141.330 141.330132000 192.168.8.7 10.241.70.31 TCP 18 1522 127 262800 54525 1522 → 54525 [PSH, ACK] Seq=8062 Ack=6697 Win=262800 Len=73

N.B. I'm new and can't upload a screenshot or the pcapng file :-(.

Anyway I find the delay spend between my workstation and the application server (141 * 2 = 4.7 s).

I also noticed that the TTL (frame 1846 & 2953) is 60. Is it correct if I said there is 68 (128-60) network componant between my workstation (192.168.8.7) and the Oracle server (10.21.70.31) ? How can I know where the time is spend ?? BR, Ali.

Hi everyone, I have an application that was migrated from on provider to another. From the new provider when a user logon it took around 5 minutes. Provider tell us that all is OK from their part. From my workstation I have run wireshak and find this in the trame :

1846 07:40:20,504 141.288 141.288268000 192.168.8.7 10.241.70.31 TCP 18 1522 129 262800 54525 1522 → 54525 [PSH, ACK] Seq=7915 Ack=6362 Win=262800 Len=75

2953 07:42:41,955 141.330 141.330132000 192.168.8.7 10.241.70.31 TCP 18 1522 127 262800 54525 1522 → 54525 [PSH, ACK] Seq=8062 Ack=6697 Win=262800 Len=73

N.B. I'm new and can't upload a screenshot or the pcapng file :-(.

Anyway I find the delay spend between my workstation and the application server (141 * 2 = 4.7 s).

I also noticed that the s). The TTL (frame 1846 & 2953) is 60. Is it correct if I said there is 68 (128-60) network componant composant between my workstation (192.168.8.7) and the Oracle server (10.21.70.31) ? How can I know where the time is spend ? BR, Ali.

Hi everyone, I have an application that was migrated from on provider to another. From the new provider when a user logon it took around 5 minutes. Provider tell us that all is OK from their part. From my workstation I have run wireshak and find this in the trame :

1846 07:40:20,504 141.288 141.288268000 192.168.8.7 10.241.70.31 TCP 18 1522 129 262800 54525 1522 → 54525 [PSH, ACK] Seq=7915 Ack=6362 Win=262800 Len=75

2953 07:42:41,955 141.330 141.330132000 192.168.8.7 10.241.70.31 TCP 18 1522 127 262800 54525 1522 → 54525 [PSH, ACK] Seq=8062 Ack=6697 Win=262800 Len=73

N.B. I'm new and can't upload a screenshot or the pcapng file :-(.

Anyway I find the delay spend between my workstation and the application server (141 * 2 = 4.7 s). ). The TTL (frame 1846 1746 & 2953) is 60. Is it correct if I said there is 68 (128-60) network composant between my workstation (192.168.8.7) and the server (10.21.70.31) ? How can I know where the time spend ? BR, Ali.

Hi everyone, I have an application that was migrated from on provider to another. From the new provider when a user logon it took around 5 minutes. Provider tell us that all is OK from their part. From my workstation I have run wireshak and find this in the trame :

1846 07:40:20,504 141.288 141.288268000 192.168.8.7 10.241.70.31 TCP 18 1522 129 262800 54525 1522 → 54525 [PSH, ACK] Seq=7915 Ack=6362 Win=262800 Len=75

2953 07:42:41,955 141.330 141.330132000 192.168.8.7 10.241.70.31 TCP 18 1522 127 262800 54525 1522 → 54525 [PSH, ACK] Seq=8062 Ack=6697 Win=262800 Len=73

N.B. I'm new and can't upload a as screenshot or the pcapng file :-(.

Anyway I find the delay spend between my workstation and the application server (141 * 2 ). The TTL (frame 1746 & 2953) is 60. Is it correct if I said there is 68 (128-60) network composant between my workstation (192.168.8.7) and the server (10.21.70.31) ? How can I know where the time spend ? BR, Ali.